Ecuatie simpla

noor Mar Mai 15, 2012 10:03 pm

solutia reala a ecuatiei(x+radical3)la a 2-10=x la a 2-(radical din 3+2)la a 2..................

**Admin** Mier Mai 16, 2012 1:27 am

noor a scris:solutia reala a ecuatiei(x+radical3)la a 2-10=x la a 2-(radical din 3+2)la a 2..................

Asa arata problema dvs. :

${\left( {x + \sqrt 3 } \right)^2} - 10 = {x^2} - {\left( {\sqrt 3 + 2} \right)^2}$

**Admin** Mier Mai 16, 2012 9:17 am

Conform afirmatilor dvs. "punctul 2 asa e scris in carte" , problema se rezolva :
$\begin{gathered} {\left( {x + \sqrt 3 } \right)^2} - 10 = {x^2} - {\left( {\sqrt 3 + 2} \right)^2} \Leftrightarrow {\left( {x + \sqrt 3 } \right)^2} - {x^2} = 10 - {\left( {\sqrt 3 + 2} \right)^2} \hfill \\ \left( {x + \sqrt 3 - x} \right)\left( {x + \sqrt 3 + x} \right) = {\left( {\sqrt {10} } \right)^2} - {\left( {\sqrt 3 + 2} \right)^2} \hfill \\ \sqrt 3 \left( {2x + \sqrt 3 } \right) = \left( {\sqrt {10} - \left( {\sqrt 3 + 2} \right)} \right)\left( {\sqrt {10} + \left( {\sqrt 3 + 2} \right)} \right) \hfill \\ x = \frac{{\frac{{\sqrt 3 }}{3}\left( {\sqrt {10} - \left( {\sqrt 3 + 2} \right)} \right)\left( {\sqrt {10} + \left( {\sqrt 3 + 2} \right)} \right) - \sqrt 3 }}{2} \hfill \\ \end{gathered}$
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