Inecuatii...

Natalia Mier Apr 11, 2012 9:50 pm

Domn' profesor, cum se fac inecuatiile de genul:

$A={x\epsilon \mathbb{N}| 96\leq x^{2}< 290}$

$E= { X\epsilon \mathbb{N}|20\leq \sqrt{X}\leq 22}$

ŞI

$B= \left \{ x \epsilon \mathbb{N}|29< x^{2}< 82 \right \}$

Multumesc mult!!!! cheers

**Admin** Joi Apr 12, 2012 9:04 pm

$A={x\epsilon \mathbb{N}| 96\leq x^{2}< 290}$

$96 \leqslant {x^2} < 290 \Leftrightarrow 96 < 100 \leqslant {x^2} \leqslant 289 < 290 \Leftrightarrow 96 < {10^2} \leqslant {x^2} \leqslant {17^2} < 290 \Rightarrow 10 \leqslant x \leqslant 17$

$E= { X\epsilon \mathbb{N}|20\leq \sqrt{X}\leq 22}$

Ridicam la a doua :
$20 \leqslant \sqrt x \leqslant 22 \Leftrightarrow {20^2} \leqslant x \leqslant {22^2}$
Deci x se afla intre numerele pătrate...

$B= \left \{ x \epsilon \mathbb{N}|29< x^{2}< 82 \right \}$

Idem problema 1.

Inecuatii...

Inecuatii...

Re: Inecuatii...